Setting a input pin via a variable

[Exerqtor]

I'm trying to make some macros with a settings sections in the top, but I'm running into one i can't figgure out how to solve 🥵

For instance, I would want to have a local variable represent the input for a endstop pin. Let's call it var.Xpin.
So in the top of the macro I have var Xpin = "io1.in"

Then somewhere farther down in the macro i want to define the X endstop with var.Xpin as the input.
I place a M574 X2 S1 P{var.Xpin} , and that's where the "fun" starts since M574 is expecting a string expression.

Sure I think, i'll slapp on a couple extra "s around the variable so it's now var Xpin = ""io1.in"" .
Well guess what that don't work either because it's "expecting a non-empty string" 🤣

I've been throwing in ^ ^ around the variable in M574, don't work, tried with a plethora of "s around the variable etc.
Is this even possible to achieve? And if it is, can someone pleeeease point me in the right direction before i start getting nosebleeds lol.

[chrishamm]

@Exerqtor This works for me:

var xEndstop = "io0.in"
M574 P{var.xEndstop} X1 S1

[Exerqtor]

@chrishamm
Yes it does, I must have been overthinking it or something. That the quotation mark around the variable wouldn't get read or something, so i slapped on a double set.
Wrote the code before i went to bed yesterday, probably bad practice doing so when sleepy.

Thanks for the help AGAIN Christian!🤦‍♂️