Upgraded rod and effector for Anycubic Kossel Liner Plus
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Hi all,
I have an Anycubic Kossel Linear Plus, or better said, I used to have since I have done so many upgrades, using a Duet 2 Wifi among others,
The next step I want to pursue is to upgrade the rod, carriage and effector for a magnetic set I found on effector for a magnetic set I found on Aliexpress
The problem is that I have no clue, nor did I found any reference on which length to buy. The offered lengths are 180, 240 and 300 mm and I only know that the Kossel Linear Plus has a rod length of 267 measured from hole center to hole center.
Has anyone experience with these? any help would be appreciated...
thanks in advance! -
Avoid that set like the plague the angle of the magnets in the effector combined with the strength of them means that as the rods get close to horizontal the magnets give way and you end up with a free floating HotEnd. you will be much better of going for a Duet smart effector and a set of Haydn rods which can be had in 288mm lengths
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AKL+ can run rods in the area of 280 to 310 with a smart effector. Slight tradeoff between Z height (good with shorter rods) vs quality at the very edge of the print (less with shorter). In reality, this is a very minor tradeoff.
I'd consider 290 or 300. Poke around different suppliers and you will find a lot of different lengths of Haydn's rods. As Dougal said, 288 is a great choice. Or, contact Haydn directly and he will custom make anything.
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thank you both for your inputs... I'm glad I asked before making any decision. If I were to change to an smart effector and those rods, were could I find compatible linear carriages?
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you could get the Alloy ones that robotdigg use but I bet you could re-use the AKL Ones the PCB Carriages that come with the Smart effector fit between the existing carriages and the linear rail sliders. Robotdigg carriages
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@Dougal1957 said in Upgraded rod and effector for Anycubic Kossel Liner Plus:
you could re-use the AKL Ones the PCB Carriages that come with the Smart effector fit between the existing carriages and the linear rail sliders
Exactly