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    Remove pullup resistor on sensor input pin

    Tuning and tweaking
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    • nyaru
      nyaru last edited by

      Hi.
      I have a sensor with analog voltage output connected to the "temp0" pin of Duet3 6HC.
      This sensor outputs 0-5.2V, so I use a voltage divider resistor to step it down to 3.3V. It uses 2kΩ, 3kΩ, and variable resistors.
      However, when the sensor output is 0V, the reported sensor value is not 0 on Duet. About 1V is applied to temp0.
      I am thinking that the pull-up resistor may be the cause.
      Can I disable the pull-up resistor on the sensor pin?

      I have set up the sensor with the following command

      M308 S0 P"temp0" Y"linear-analog" A"laser" B0 C100 
      

      Thanks

      alankilian 1 Reply Last reply Reply Quote 0
      • alankilian
        alankilian @nyaru last edited by

        @nyaru

        Maybe you should use one of the other pins as an analog input?

        ANALOG INPUT capable pins.

        If not, THIS PDF shows how THERMISTER0 is connected.

        You could remove R28 and jumper over R29 if the capacitor is OK. Otherwise, remove C55

        Capture.PNG

        SeemeCNC Rostock Max V3 converted to V3.2 with a Duet2 Ethernet Firmware 3.2 and SE300

        nyaru 1 Reply Last reply Reply Quote 0
        • nyaru
          nyaru @alankilian last edited by

          @alankilian
          I changed to use io pin as analog input.
          It works.
          Thank you!!!

          alankilian 1 Reply Last reply Reply Quote 0
          • alankilian
            alankilian @nyaru last edited by

            @nyaru

            AWESOME!

            SeemeCNC Rostock Max V3 converted to V3.2 with a Duet2 Ethernet Firmware 3.2 and SE300

            1 Reply Last reply Reply Quote 0
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